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In an experiment , the following observa...

In an experiment , the following observations were recorded:
`L = 2.820 m , M = 3.00 kg , l = 0.087 cm , diameter , D = 0.041 cm`. Taking ` g = 9.81 m s^(-2)` and using the formula , `Y = ( 4MgL)/( pi D^(2) l)` , find the maximum permissible error in `Y`.

A

In this experiment to calculate the maximum permissible error, we can consider, `(Delta Y)/(Y)=(Delta M)/(M)+(Delta L)/(L)+(Delta g)/(g)-2((Delta d)/(d))-((Delta a)/(a))`

B

In this experiment to calculate the maximum permissible error, we can consider, `(Delta Y)/(Y)=(Delta M)/(M)+(Delta L)/(L)-2((Delta d)/(d))-((Delta a)/(a))`

C

In this experiment to calculate the maximum permissible error, we can consider, `(Delta Y)/(Y)=(Delta M)/(M)+(Delta L)/(L)+2((Delta d)/(d))+((Delta a)/(a))`

D

The percentage error in the calculation of Y is 6.36%

Text Solution

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The correct Answer is:
C, D
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