Home
Class 11
PHYSICS
If mu is the permeability and in is the ...

If `mu` is the permeability and `in` is the permittivity then `(1)/(sqrt(mu in))` is equal to

A

Speed of sound

B

Speed of light in vaccum

C

Speed of sound in medium

D

Speed of light in medium

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to relate the quantities given: permeability (μ) and permittivity (ε). We are asked to find the expression for \( \frac{1}{\sqrt{\mu \epsilon}} \). ### Step-by-Step Solution: 1. **Understanding the Definitions**: - Permeability (μ) is a measure of how much a material can support the formation of a magnetic field within itself. - Permittivity (ε) is a measure of how much electric field is 'permitted' to pass through a material. 2. **Recall the Speed of Light Formula**: - The speed of light in a vacuum (c) is given by the equation: \[ c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \] where \( \mu_0 \) is the permeability of free space (vacuum) and \( \epsilon_0 \) is the permittivity of free space (vacuum). 3. **Generalizing for Any Medium**: - For a medium with permeability (μ) and permittivity (ε), the speed of light (v) in that medium can be expressed as: \[ v = \frac{1}{\sqrt{\mu \epsilon}} \] 4. **Finding the Expression**: - From the equation above, we can directly see that: \[ \frac{1}{\sqrt{\mu \epsilon}} = v \] - Here, \( v \) represents the speed of light in the medium characterized by the given permeability and permittivity. 5. **Conclusion**: - Therefore, the final answer is: \[ \frac{1}{\sqrt{\mu \epsilon}} = v \] - Where \( v \) is the speed of light in the medium.
Promotional Banner

Similar Questions

Explore conceptually related problems

If mu_(0) be the permeability and epsilon_(0) be the permittivity of a medium, then its refractive index is given by

The speed of an electromagnetic wave in a material medium is given by n=(1)/(sqrt(mu epsilon)), m being the permeability of the medium and e its permittivity. How does its frequency change ?

In a electro magnetic wave the expression for electric field is given by E=50 sin (omegat-kx) the permeability is given mu=4mu_(0) & permittivity epsi_(0)=epsi_(r) , then find the average intensity delivered.

Which of the following combinations has the dimension of electrical resistance ( in_(0) is the permittivity of vacuum and mu_(0) is the permeability of vacuum)?

Which of the following combinations has the dimension of electrical resistance ( in_(0) is the permittivity of vacuum and mu_(0) is the permeability of vacuum)?

If int 2/(2-x)^2 ((2-x)/(2+x))^(1//3)\ dx = lambda ((2+x)/(2-x))^mu + c where lambda and mu are rational number in its simplest form then (lambda+1/mu) is equal to

Which of the following product of e , h , mu , G ( where mu is permeability ) be taken so that the dimensions of the product are same as that of the speed of light ?

If the integral I=int(dx)/(x^(10)+x)=lambda ln ((x^(9))/(1+x^(mu)))+C , (where, C is the constant of integration) then the value of (1)/(lambda)+mu is equal to

Which of the following does not have the dimensions of velocity ? ( Given epsilon_(0) is the permittivity of free space , mu_(0) is the permeability of free space , v is frequency , lambda is wavelength , P is the pressure , and rho is density , k is wave number , omega is the the angular frequency) (1) omega k (2) v lambda (3)1/ sqrt(epsilon_(0) mu_(0)) (4) sqrt(P/rho)