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The number of significant figures in 6.0...

The number of significant figures in `6.023xx10^(23)"mole"^(-1)` is

A

4

B

3

C

2

D

23

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of significant figures in the number \(6.023 \times 10^{23} \, \text{mole}^{-1}\), we can follow these steps: ### Step 1: Identify the digits in the number The number given is \(6.023\). Here, we will look at each digit in this number. ### Step 2: Apply the rules of significant figures 1. **Non-zero digits are significant**: In \(6.023\), the digits \(6\), \(2\), and \(3\) are non-zero and thus significant. 2. **Zeros between non-zero digits are significant**: The digit \(0\) in \(6.023\) is between \(6\) and \(2\), making it significant as well. 3. **Powers of ten do not affect significant figures**: The \(10^{23}\) part does not influence the count of significant figures. ### Step 3: Count the significant figures Now, we can count the significant figures: - The digits \(6\), \(0\), \(2\), and \(3\) are all significant. - Therefore, the total number of significant figures in \(6.023\) is \(4\). ### Conclusion The number of significant figures in \(6.023 \times 10^{23} \, \text{mole}^{-1}\) is \(4\). ### Final Answer Thus, the correct option is **A: 4**. ---
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