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A block of mass m(1) is in equilibrium ...

A block of mass `m_(1)` is in equilibrium on an inclined plane. Ignoring the friction at the pulley and mass of the string, the friction on the block is :

A

`(m _(1) g sin theta m _(2) g ) ` up the pane when `m _(2) lt m _(1) sin theta `

B

`(m_(2) g -m_(1) g sin theta)` down the plane when `m _(2) gt m _(1) sin theta `

C

Zero, when `m _(2)= m _(1) sin theta `

D

`mu m_(1) g cos theta ` when `m _(2) ge m_(1) (sin theta + mu cos theta)`

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The correct Answer is:
A, B, C, D
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