Home
Class 11
PHYSICS
If coefficient of friction between all s...

If coefficient of friction between all surfaces is 0.4, then the minimum horizontal force F to have the equilibrium of the system will be, `(g=10m//s^(2))`

A

`62.5N`

B

`150N`

C

`135N`

D

`50N`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

If the coefficient of friction between all surface figure is 0.4 then find the minimum force F to have equilibrium of the system.

A block of mass 10 kg is placed on the rough horizontal surface. A pulling force F is acting on the block which makes an angle theta above the horizontal. If coefficient of friction between block and surface is 4/3 then minimum value of force required to just move the block is (g = 10 m/s^2)

A block is projected with speed 20 m/s on a rough horizontal surface. The coefficient of friction (mu) between the surface varies with time (t) as shown in figure. The speed of body at the end of 4 second will be (g=10m//s^(2))

The coefficient of friction between the block and the surface is 0.25. For the system to be in equilibrium, the value of M is

Two blocks A and B of masses 10 kg and 15 kg are placed in contact with each other rest on a rough horizontal surface as shown in the figure. The coefficient of friction between the blocks and surface is 0.2. A horizontal force of 200 N is applied to block A. The acceleration of the system is ("Take g"=10ms^(-2))

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

A block of mass 20 kg is acted upon by a force F=30N at an angle 53^@ with horizontal in downward direction as shown. The coefficient of friction between the block and the forizontal surface is 0.2 . The friction force acting on the block by the ground is (g=10(m)/(s^2) )

A block of mass 20 kg is acted upon by a force F=30N at an angle 53^@ with horizontal in downward direction as shown. The coefficient of friction between the block and the forizontal surface is 0.2 . The friction force acting on the block by the ground is (g=10(m)/(s^2) )

A block of mass 20 kg is acted upon by a force F=30N at an angle 53^@ with horizontal in downward direction as shown. The coefficient of friction between the block and the forizontal surface is 0.2 . The friction force acting on the block by the ground is (g=10(m)/(s^2) )

A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 . When a force F=40N is applied, the acceleration of the block will be (g=10m//s^(2)) .