Home
Class 11
PHYSICS
A particle is going parallel to x-axis w...

A particle is going parallel to x-axis with constant speed V at a distance 'a' from the axis. Find its angular velocity about an axis passing the origin O, at the instant when radial vector of the particle makes angle `theta` with the x-axis

A

`(V)/(a)sin^(2)theta`

B

`(V)/(asin(theta)`

C

`(2V)/(a)sin^(2)theta`

D

`(V)/(2a)sin^(2)theta`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the angular velocity of a particle moving parallel to the x-axis at a constant speed \( V \) and at a distance \( a \) from the x-axis, when the radial vector makes an angle \( \theta \) with the x-axis. ### Step-by-Step Solution: 1. **Understand the Setup**: - The particle is moving parallel to the x-axis with a constant speed \( V \). - It is located at a distance \( a \) from the x-axis. - The radial vector from the origin (O) to the particle makes an angle \( \theta \) with the x-axis. 2. **Identify the Position of the Particle**: - The position of the particle can be represented in Cartesian coordinates as \( (x, y) \). - Since it is moving parallel to the x-axis and at a distance \( a \) from the x-axis, we can denote the position as \( (x, a) \). 3. **Determine the Radial Vector**: - The radial vector \( \vec{r} \) from the origin to the particle is given by: \[ \vec{r} = x \hat{i} + a \hat{j} \] - The angle \( \theta \) is the angle between this radial vector and the x-axis. 4. **Calculate the Perpendicular Distance**: - The perpendicular distance from the axis of rotation (the x-axis) to the line of motion of the particle is given by: \[ d = a \sin(\theta) \] - This is because the radial vector makes an angle \( \theta \) with the x-axis, and the vertical component of the distance is \( a \sin(\theta) \). 5. **Determine the Angular Velocity**: - The angular velocity \( \omega \) can be calculated using the formula: \[ \omega = \frac{V}{d} \] - Substituting the expression for \( d \): \[ \omega = \frac{V}{a \sin(\theta)} \] ### Final Answer: The angular velocity \( \omega \) of the particle about the axis passing through the origin is: \[ \omega = \frac{V}{a \sin(\theta)} \]
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle mass parallel to x-axis with constant velocity v as shown in the figure. The angular velocity of the particle about the origin O

A particle is moving with constant speed v along x - axis in positive direction. Find the angular velocity of the particle about the point (0, b), when position of the particle is (a, 0).

A particle is moving with constant speed v along the line y = a in positive x -direction. Find magnitude of its angular velocity about orgine when its position makes an angle theta with x-axis.

A particle is moving with constant speed v along the line y = a in positive x -direction. Find magnitude of its angular velocity about orgine when its position makes an angle theta with x-axis.

A particle is moving along a straight line parallel to x-axis with constant velocity. Find angular momentum about the origin in vector form :

A particle is moving parallel to x-axis as shown in the figure. The angular velocity of the particle about the origin is

Find locus of a point so that its distance from the axis of x is always one half its distance from the origin.

A particle moving parallel to x-axis as shown in fig. such that at all instant the y-axis component of its position vector is constant and is equal to 'b'. Find the angular velocity of the particle about the origin when its radius vector makes angle theta from the axis.

A particle of mass m is moving with constant velocity v parallel to the x-axis as shown in the figure. Its angular momentum about origin O is

An electric point dipole is placed at the origin O with its dipolemoment along the X-axis . A point A is at a distance r from the origin such that OA makes an angle pi//3 with the X -axis if the electric field vec( E) due to the dipole at A makes an angle theta with the positive X-axis, the value of theta is