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If two particles are moving on same circ...

If two particles are moving on same circle in same plane with different angular velocities `omega_(1)` and `omega_(2)` and different time period `T_(1)`, and `T_(2)` in same sense, then the time taken by 2 to complete one revolution w.r.t particle l is

A

`T= (T_(1)T_(2))/(T_(2)-T_(1))`

B

`T= (T_(1)+T_(2))/(2)`

C

`T= (T_(1)T_(2))/(T_(1)+T_(2))`

D

`T_(2)-T_(1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the time taken by particle 2 to complete one revolution with respect to particle 1. Let's break down the solution step by step. ### Step-by-Step Solution: 1. **Understanding Angular Velocity and Time Period**: - The angular velocity \( \omega \) and time period \( T \) are related by the formula: \[ T = \frac{2\pi}{\omega} \] - For particle 1, we have: \[ T_1 = \frac{2\pi}{\omega_1} \] - For particle 2, we have: \[ T_2 = \frac{2\pi}{\omega_2} \] 2. **Finding Relative Angular Velocity**: - Since both particles are moving in the same direction, the relative angular velocity \( \omega_{\text{relative}} \) between the two particles is given by: \[ \omega_{\text{relative}} = \omega_1 - \omega_2 \] 3. **Expressing Relative Angular Velocity in Terms of Time Periods**: - We can express \( \omega_1 \) and \( \omega_2 \) in terms of \( T_1 \) and \( T_2 \): \[ \omega_1 = \frac{2\pi}{T_1}, \quad \omega_2 = \frac{2\pi}{T_2} \] - Substituting these into the relative angular velocity equation gives: \[ \omega_{\text{relative}} = \frac{2\pi}{T_1} - \frac{2\pi}{T_2} \] 4. **Finding the Time Taken for One Revolution Relative to Particle 1**: - The time taken for particle 2 to complete one revolution with respect to particle 1 is given by: \[ T_{\text{relative}} = \frac{2\pi}{\omega_{\text{relative}}} \] - Substituting the expression for \( \omega_{\text{relative}} \): \[ T_{\text{relative}} = \frac{2\pi}{\left(\frac{2\pi}{T_1} - \frac{2\pi}{T_2}\right)} \] - Simplifying this expression: \[ T_{\text{relative}} = \frac{2\pi}{2\pi\left(\frac{1}{T_1} - \frac{1}{T_2}\right)} = \frac{1}{\left(\frac{1}{T_1} - \frac{1}{T_2}\right)} \] - This can be rewritten as: \[ T_{\text{relative}} = \frac{T_1 T_2}{T_2 - T_1} \] 5. **Final Result**: - The time taken by particle 2 to complete one revolution with respect to particle 1 is: \[ T_{\text{relative}} = \frac{T_1 T_2}{T_2 - T_1} \]
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