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A large mass M hangs stationary at the e...

A large mass M hangs stationary at the end of a light string that passes through a smooth fixed tube small mass m that moves around in horizontal circular path, If 1 is the length of the string from m to the top end of the tube and `theta` is angle between this part and vertical part of the string as shown in the fig, then time taken by m to complete one circle is equal to

A

`2pisqrt((1)/(gsintheta))`

B

`2pisqrt((1)/(gcostheta))`

C

`2pisqrt((ml)/(gMsintheta))`

D

`2pisqrt((1m)/(gM))`

Text Solution

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The correct Answer is:
D
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