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A block of mass m is kept on rough horiz...

A block of mass m is kept on rough horizontal tum table at a distance r from centre of table. Coefficient of friction between turn table and block is `mu`. Now turn table starts rotating with uniform angular acceleration `alpha`.
Find the time after which slippping occurs between block and turn table

A

`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))^(1//4)`

B

`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))^(1//3)`

C

`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))^(1//2)`

D

`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A
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