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If omega(1),omega(2)omega(3)omega(4) are...

If `omega_(1),omega_(2)omega_(3)omega_(4)` are angular velocities of rotation of earth, seconds hand, minutes hand. hours hand of a watch respectively these values in decreasing order is

A

`omega_(1),omega_(4)omega_(3)omega_(2)`

B

`omega_(2),omega_(3)omega_(4)omega_(1)`

C

`omega_(1),omega_(2)omega_(3)omega_(4)`

D

`omega_(4),omega_(3)omega_(2)omega_(1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the angular velocities of the Earth, seconds hand, minutes hand, and hour hand, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Time Periods**: - The time period \( T \) is the time taken for one complete rotation. - For the Earth, \( T_1 = 24 \) hours. - For the seconds hand, \( T_2 = 60 \) seconds. - For the minutes hand, \( T_3 = 60 \) minutes = \( 3600 \) seconds. - For the hour hand, \( T_4 = 12 \) hours. 2. **Convert All Time Periods to the Same Unit**: - Convert hours to seconds for consistency: - \( T_1 = 24 \times 3600 = 86400 \) seconds. - \( T_4 = 12 \times 3600 = 43200 \) seconds. - Now we have: - \( T_1 = 86400 \) seconds (Earth) - \( T_2 = 60 \) seconds (Seconds hand) - \( T_3 = 3600 \) seconds (Minutes hand) - \( T_4 = 43200 \) seconds (Hour hand) 3. **Determine the Angular Velocities**: - Angular velocity \( \omega \) is inversely proportional to the time period \( T \): \[ \omega = \frac{2\pi}{T} \] - Therefore, the relationship between angular velocities and time periods is: - \( \omega_1 \propto \frac{1}{T_1} \) - \( \omega_2 \propto \frac{1}{T_2} \) - \( \omega_3 \propto \frac{1}{T_3} \) - \( \omega_4 \propto \frac{1}{T_4} \) 4. **Rank the Time Periods**: - From the calculated time periods: - \( T_1 = 86400 \) seconds (Earth) - longest - \( T_4 = 43200 \) seconds (Hour hand) - \( T_3 = 3600 \) seconds (Minutes hand) - \( T_2 = 60 \) seconds (Seconds hand) - shortest - Thus, in terms of time period: \( T_1 > T_4 > T_3 > T_2 \) 5. **Rank the Angular Velocities**: - Since angular velocity is inversely proportional to the time period, we have: - \( \omega_1 < \omega_4 < \omega_3 < \omega_2 \) - Therefore, in decreasing order of angular velocities: - \( \omega_2 > \omega_3 > \omega_4 > \omega_1 \) ### Final Answer: The angular velocities in decreasing order are: \[ \omega_2, \omega_3, \omega_4, \omega_1 \]
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