Home
Class 11
PHYSICS
A stationary wheel starts rotating about...

A stationary wheel starts rotating about its own axis at constant angular acceleration. If the wheel completes 50 rotations in first 2 seconds, then the number of rotations made by itin next two seconds is

A

75

B

100

C

125

D

150

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the principles of rotational motion and the equations of motion for constant angular acceleration. ### Step 1: Understanding the Problem We have a wheel that starts from rest (initial angular velocity, \( \omega_i = 0 \)) and rotates with a constant angular acceleration (\( \alpha \)). It completes 50 rotations in the first 2 seconds. ### Step 2: Convert Rotations to Radians Since the equations of motion are typically in radians, we need to convert the number of rotations into radians: \[ \theta = 50 \text{ rotations} \times 2\pi \text{ radians/rotation} = 100\pi \text{ radians} \] ### Step 3: Use the Angular Displacement Equation We will use the second equation of motion for angular displacement: \[ \theta = \omega_i t + \frac{1}{2} \alpha t^2 \] Substituting the known values: \[ 100\pi = 0 \cdot 2 + \frac{1}{2} \alpha (2^2) \] This simplifies to: \[ 100\pi = 2\alpha \] From this, we can solve for \( \alpha \): \[ \alpha = \frac{100\pi}{2} = 50\pi \text{ radians/second}^2 \] ### Step 4: Find the Final Angular Velocity After 2 Seconds Using the first equation of motion for angular velocity: \[ \omega_f = \omega_i + \alpha t \] Substituting the known values: \[ \omega_f = 0 + (50\pi)(2) = 100\pi \text{ radians/second} \] ### Step 5: Calculate the Number of Rotations in the Next 2 Seconds Now, we need to find out how many rotations the wheel makes in the next 2 seconds (from \( t = 2 \) seconds to \( t = 4 \) seconds). The initial angular velocity for this interval is \( \omega_i = 100\pi \) radians/second. Using the same angular displacement equation: \[ \theta = \omega_i t + \frac{1}{2} \alpha t^2 \] Here, \( t = 2 \) seconds, \( \alpha = 50\pi \): \[ \theta = (100\pi)(2) + \frac{1}{2}(50\pi)(2^2) \] Calculating this gives: \[ \theta = 200\pi + \frac{1}{2}(50\pi)(4) = 200\pi + 100\pi = 300\pi \text{ radians} \] ### Step 6: Convert Radians Back to Rotations Now, convert the angular displacement back to rotations: \[ \text{Number of rotations} = \frac{300\pi}{2\pi} = 150 \text{ rotations} \] ### Final Answer The number of rotations made by the wheel in the next two seconds is **150 rotations**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A wheel is rotating about its axis at a constant angular velocity. If suddenly an object sticks to it on the rim, then its M.I. will:

A fly wheel is rotating about its own axis at an angular velocity 11 rads^(-1) , its angular velocity in revolution per minute is

A wheel rotating wilth unifrom angular acceleration covers 50 revolutions in the first five seconds after the start. Find the angular acceleration and the angular velocity at the end of five seconds.

The angular velocity of a wheel rotating with constant angular acceleration, changes from 2 rad/s to 6 rad/s in a time interval of 31.4 s. The number of rotations made by the wheel in this interval of time is

The radii of the wheel of a car is 28 cm. Find the number of rotations made by the wheel in order to cover a distance of 4.4 km ?

A wheel rotates with a constant acceleration of 2.0rad/s^2 . If the wheel starts from rest, how many revolutions will it make in the first 10 seconds?

A wheel initially at rest, is rotated with a uniform angular acceleration. The wheel rotates through an angle theta_(1) in first one second and through an additional angle theta_(2) in the next one second. The ratio theta_(2)//theta_(1) is :

A solid body starts rotating about a stationary axis with an angular acceleration alpha=(2.0xx10^(-2))t rad//s^(2) here t is in seconds. How soon after the beginning of rotation will the total acceleration vector of an arbitrary point of the body form an angle theta=60^(@) with its velocity vector?

A wheel rotates with a constant acceleration of 2.0(rad)/s^2 . If the wheel starts from rest, how many revolutions will it make in the first 10 seconds?

A wheel initially at rest, is rotated with a uniform angular acceleration. The wheel rotates through an angle theta_(1) in the first one second and through an additional angle theta_(2) in the next one second. The ratio theta_(1)//theta_(2) is: