Home
Class 11
PHYSICS
A ceiling fan is rotating about its own ...

A ceiling fan is rotating about its own axis with uniform angular velocity `omega`. The electric current is switched off then due to constant opposing torque its angular velocity is reduced to `2omega//3` as it completes 30 rotations. The number of rotations further it makes before coming to rest is

A

18

B

12

C

9

D

24

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Identify the given values - Initial angular velocity, \( \omega_0 = \omega \) - Final angular velocity after 30 rotations, \( \omega = \frac{2\omega}{3} \) - Number of rotations completed, \( \theta = 30 \) ### Step 2: Use the kinematic equation for rotational motion The kinematic equation for angular motion is given by: \[ \omega^2 = \omega_0^2 + 2\alpha\theta \] Where: - \( \omega \) is the final angular velocity - \( \omega_0 \) is the initial angular velocity - \( \alpha \) is the angular acceleration - \( \theta \) is the angular displacement in rotations Substituting the known values: \[ \left(\frac{2\omega}{3}\right)^2 = \omega^2 + 2\alpha(30) \] ### Step 3: Simplify the equation Calculating \( \left(\frac{2\omega}{3}\right)^2 \): \[ \frac{4\omega^2}{9} = \omega^2 + 60\alpha \] Rearranging gives: \[ \frac{4\omega^2}{9} - \omega^2 = 60\alpha \] \[ \frac{4\omega^2 - 9\omega^2}{9} = 60\alpha \] \[ -\frac{5\omega^2}{9} = 60\alpha \] Thus, we find: \[ \alpha = -\frac{5\omega^2}{540} = -\frac{\omega^2}{108} \] ### Step 4: Calculate the number of rotations before coming to rest Now, we need to find the number of rotations \( n \) it makes before coming to rest (when \( \omega = 0 \)): Using the same kinematic equation: \[ \left(\frac{2\omega}{3}\right)^2 = 0 + 2\alpha n \] Substituting for \( \alpha \): \[ \frac{4\omega^2}{9} = 2\left(-\frac{\omega^2}{108}\right)n \] This simplifies to: \[ \frac{4\omega^2}{9} = -\frac{2\omega^2}{108}n \] Cancelling \( \omega^2 \) (assuming \( \omega \neq 0 \)): \[ \frac{4}{9} = -\frac{2}{108}n \] Cross-multiplying gives: \[ 4 \cdot 108 = -2 \cdot 9n \] \[ 432 = -18n \] Thus: \[ n = -\frac{432}{18} = -24 \] Since the number of rotations cannot be negative, we take the absolute value: \[ n = 24 \] ### Final Answer The number of rotations it makes before coming to rest is **24**.
Promotional Banner

Similar Questions

Explore conceptually related problems

A circular disc is rotating about its own axis at uniform angular velocity omega . The disc is subjected to uniform angular retardation by which its angular velocity is decreased to omega//2 during 120 rotations., The number of rotations further made by it before coming to rest is

A cylinder of water, is rotating about its own axis with uniform angular velocity ω. The shape of free surface of water will be

When a celling fan is switched off, its angular velocity falls to half while it makes 36 rotations. How many more rotations will it make before coming to rest ?

When a celling fan is switched off, its angular velocity falls to half while it makes 36 rotations. How many more rotations will it make before coming to rest ?

Angular momentum of a rigid body rotating about a fixed Axis with angular velocity vec omega

A disc is rotaing with an angular velocity omega_(0) . A constant retarding torque is applied on it to stop the disc. The angular velocity becomes (omega_(0))/(2) after n rotations. How many more rotations will it make before coming to rest ?

When a ceiling fan is switched off, its angular velocity reduces to 50% while it makes 36 rotations. How many more rotations will it make before coming to rest?(Assume uniform angular retardation)

A circular disc is rotating about its own axis at an angular velocity omega . If P is exact midpoint of dise between axis and rim of disc then angular velocity of Pis

A non-conducting disc having unifrom positive charge Q , is rotating about its axis with unifrom angular velocity omega .The magnetic field at the centre of the disc is.

A ceiling fan rotates about its own axis with some angular velocity. When the fan is switched off, the angular velocity becomes (1/4) th of the original in time 't' and 'n' revolutions are made in that time. The number of revolutions made by the fan during the time interval between switch of and rest are (Angular retardation is uniform)