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A particle moves along the plane traject...

A particle moves along the plane trajectory y(x) with constant speed 'v'. The trajectory has the form of a parabola `y = ax^(2)` where 'a' is a positive constant. Then the radius of curvature of the trajectory at the point x=0 is

A

`(1)/(2a)`

B

`(1)/(4a)`

C

`(1)/(3a)`

D

`(1)/(a)`

Text Solution

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The correct Answer is:
To find the radius of curvature of the trajectory given by the equation \( y = ax^2 \) at the point \( x = 0 \), we can follow these steps: ### Step 1: Understand the Formula for Radius of Curvature The radius of curvature \( R \) for a curve defined by \( y = f(x) \) can be calculated using the formula: \[ R = \frac{(1 + (dy/dx)^2)^{3/2}}{d^2y/dx^2} \] ### Step 2: Differentiate the Function Given the function \( y = ax^2 \): 1. First, we need to find the first derivative \( dy/dx \): \[ \frac{dy}{dx} = \frac{d}{dx}(ax^2) = 2ax \] ### Step 3: Find the Second Derivative 2. Next, we find the second derivative \( d^2y/dx^2 \): \[ \frac{d^2y}{dx^2} = \frac{d}{dx}(2ax) = 2a \] ### Step 4: Evaluate at \( x = 0 \) 3. Now, we evaluate both derivatives at \( x = 0 \): - \( \frac{dy}{dx} \) at \( x = 0 \): \[ \frac{dy}{dx} \bigg|_{x=0} = 2a(0) = 0 \] - \( \frac{d^2y}{dx^2} \) is constant: \[ \frac{d^2y}{dx^2} = 2a \] ### Step 5: Substitute into the Radius of Curvature Formula 4. Substitute these values into the radius of curvature formula: \[ R = \frac{(1 + (0)^2)^{3/2}}{2a} = \frac{1^{3/2}}{2a} = \frac{1}{2a} \] ### Conclusion Thus, the radius of curvature of the trajectory at the point \( x = 0 \) is: \[ R = \frac{1}{2a} \]
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