On heating glucose with Fehling solution , we get a precipitate whose colour is

Options

A. Orange
B. Red
C. Black
D. White

Answer

To solve the question regarding the color of the precipitate formed when heating glucose with Fehling's solution, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Glucose as an Aldehyde**:
- Glucose is a simple sugar that has an aldehyde functional group. Its chemical formula is C6H12O6. In its structural form, it can be represented as an aldehyde (CHO) followed by hydroxyl groups.

2. **Understand Fehling's Solution**:
- Fehling's solution consists of two components: Fehling's A (copper(II) sulfate) and Fehling's B (potassium sodium tartrate). When mixed, they form a blue solution due to the presence of Cu²⁺ ions.

3. **Reaction Between Glucose and Fehling's Solution**:
- When glucose (an aldehyde) is heated with Fehling's solution, it reduces the Cu²⁺ ions to Cu⁺ ions. This reduction leads to the formation of copper(I) oxide (Cu2O).

4. **Color of the Precipitate**:
- The copper(I) oxide (Cu2O) that is formed during this reaction precipitates out of the solution and has a characteristic brick-red color.

5. **Conclusion**:
- Therefore, when glucose is heated with Fehling's solution, the precipitate formed is brick-red in color.

### Final Answer:
The color of the precipitate obtained when heating glucose with Fehling's solution is **brick-red**.

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