In a woody dicot stem twenty spring woods and twenty autumn woods are present. What is the approximate age of that tree

Options

A. 10 Years
B. 40 Years
C. 5 Years
D. 20 Years

Answer

To determine the approximate age of a woody dicot stem with 20 spring woods and 20 autumn woods, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of the Tree Rings**:
- In woody dicotyledonous plants, the growth rings (or annual rings) are formed each year. Each year typically consists of two types of wood: spring wood (formed during the growing season) and autumn wood (formed later in the year).

2. **Identify the Number of Rings**:
- The problem states that there are 20 spring woods and 20 autumn woods present in the stem.

3. **Calculate Total Annual Rings**:
- Each year contributes one spring wood and one autumn wood. Therefore, the total number of annual rings is the sum of the spring and autumn woods.
- Total annual rings = Number of spring woods + Number of autumn woods = 20 + 20 = 40.

4. **Determine the Age of the Tree**:
- Since each pair of spring and autumn woods represents one year of growth, we can calculate the age of the tree by dividing the total number of rings by 2 (since each year contributes one spring and one autumn wood).
- Age of the tree = Total annual rings / 2 = 40 / 2 = 20 years.

5. **Conclusion**:
- The approximate age of the tree is 20 years.

### Final Answer:
The approximate age of the tree is **20 years**.

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