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For the equilibrium 2SO3(g) leftrightarr...

For the equilibrium `2SO_3(g) leftrightarrow 2SO_2(g)+O_2(g)` the partial pressure `SO_3,SO_2 and O_2` gases , at 650 K are respectively 0.3 bar ,0.6 bar and 0.4 bar. IF the moles of both the oxides of sulphur are so adjusted as equal, what will be the partial pressure of `O_2`.

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To solve the problem, we need to determine the partial pressure of \( O_2 \) when the moles of \( SO_2 \) and \( SO_3 \) are made equal at equilibrium. ### Step-by-Step Solution: 1. **Write the Equilibrium Expression**: The equilibrium reaction is given as: \[ 2SO_3(g) \leftrightarrow 2SO_2(g) + O_2(g) ...
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