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At equilibrium AB5 (g) leftrightarrow AB...

At equilibrium `AB_5 (g) leftrightarrow AB_3(g) +B_2(g)` the concentrations of `AB_5 and AB_3` are 0.2 and 0.1 `mol L^-1` respectively. If `K_c=0.5 mol L^-1` calculate the equilibrium concentration of `B_2`.

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To solve the problem, we need to find the equilibrium concentration of \( B_2 \) given the equilibrium concentrations of \( AB_5 \) and \( AB_3 \), and the equilibrium constant \( K_c \). ### Step-by-Step Solution: **Step 1: Write the equilibrium expression.** For the reaction: \[ AB_5 (g) \leftrightarrow AB_3(g) + B_2(g) \] ...
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