Home
Class 11
PHYSICS
Force acting on a particle is (2hati+3ha...

Force acting on a particle is `(2hati+3hatj)N`. Work done by this force is zero, when a particle is moved on the line `3y+kx=5`. Here value of k is

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Force acting on a particale is (2hat(i)+3hat(j))N . Work done by this force is zero, when the particle is moved on the line 3y+kx=5 . Here value of k is ( Work done W=vec(F).vec(d))

Force acting on a particale is (2hat(i)+3hat(j))N . Work done by this force is zero, when the particle is moved on the line 3y+kx=5 . Here value of k is ( Work done W=vec(F).vec(d))

A force vecF = ( 3hati + 4hatj) N is acting on a particle. Work done by the force is zero, when particle is moving on the line 2y + Px = 2 , the value of P is

Force acting on a pasrticle is vecF = (alpha y hati +beta xy hatj) . Find the work done by this force, when pasrticle is moved alolng the line 2x = 3y from origin to the point (3,2) {take quantities in SI units and alpha = 1, beta = 1 }

The gravitational field in a region is given by E = (2 hati + 3 hatj) N//kg . Find the work done by the gravitational filed when a particle of mass 1 kg is moved on the line 3y+ 2X = 5 from (1 m,1m) to (-2 m, 3m) .

The force F acting on a particle is moving in a straight line as shown in figure. What is the work done by the force on the particle in the 4 m of the trajectory?

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = 2a . Here, k is a positive constant.

A force bar F = (3hat i-4 hat j +b hat k)N is acting on the particle which is moving from point A ( 0-1, 1) m to the point B(2, 2 3) m If net work done by the force on the particle is zero then value of b is

The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2kg . Work done by all the forces acting on the particle in time interval between t=0 to t=10s is

The power supplied by a force acting on a particle moving in a straight line is constant. The velocity of the particle varies with displacement as x^(1/K) . Find the value of K.