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The ratio of energy required to accelera...

The ratio of energy required to accelerated a car from rest to `20ms^(-1)` to the energy needed to acceelerate from `20ms^(-1)` to `40ms^(-1)` is

A

`1:1`

B

`1:3`

C

`1:2`

D

`1:4`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of energy required to accelerate a car from rest to \(20 \, \text{m/s}\) and from \(20 \, \text{m/s}\) to \(40 \, \text{m/s}\), we will use the concept of kinetic energy. The work done in accelerating the car is equal to the change in kinetic energy. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy**: The kinetic energy (KE) of an object is given by the formula: \[ KE = \frac{1}{2} mv^2 \] where \(m\) is the mass of the object and \(v\) is its velocity. 2. **Calculate the Energy Required to Accelerate from Rest to \(20 \, \text{m/s}\)**: - Initial velocity \(u_1 = 0 \, \text{m/s}\) (at rest) - Final velocity \(v_1 = 20 \, \text{m/s}\) - Change in kinetic energy (\(\Delta KE_1\)): \[ \Delta KE_1 = KE_{final} - KE_{initial} = \frac{1}{2} m (v_1^2) - \frac{1}{2} m (u_1^2) \] \[ \Delta KE_1 = \frac{1}{2} m (20^2) - \frac{1}{2} m (0^2) = \frac{1}{2} m (400) = 200m \] 3. **Calculate the Energy Required to Accelerate from \(20 \, \text{m/s}\) to \(40 \, \text{m/s}\)**: - Initial velocity \(u_2 = 20 \, \text{m/s}\) - Final velocity \(v_2 = 40 \, \text{m/s}\) - Change in kinetic energy (\(\Delta KE_2\)): \[ \Delta KE_2 = KE_{final} - KE_{initial} = \frac{1}{2} m (v_2^2) - \frac{1}{2} m (u_2^2) \] \[ \Delta KE_2 = \frac{1}{2} m (40^2) - \frac{1}{2} m (20^2) = \frac{1}{2} m (1600) - \frac{1}{2} m (400) \] \[ \Delta KE_2 = \frac{1}{2} m (1600 - 400) = \frac{1}{2} m (1200) = 600m \] 4. **Finding the Ratio of Energies**: Now we can find the ratio of the energy required for the two cases: \[ \text{Ratio} = \frac{\Delta KE_1}{\Delta KE_2} = \frac{200m}{600m} = \frac{200}{600} = \frac{1}{3} \] 5. **Final Answer**: The ratio of the energy required to accelerate from rest to \(20 \, \text{m/s}\) to the energy needed to accelerate from \(20 \, \text{m/s}\) to \(40 \, \text{m/s}\) is: \[ 1 : 3 \]
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