Home
Class 11
PHYSICS
A body is projected vertically up with a...

A body is projected vertically up with a velocity of 60 m/s. The percentage of its initial kinetic energy converted into potential energy after 3 s is `(g=10ms^(-2))`

A

0.25

B

0.75

C

0.5

D

0.875

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the percentage of the initial kinetic energy that is converted into potential energy after 3 seconds for a body projected vertically upward with an initial velocity of 60 m/s. Given that \( g = 10 \, \text{m/s}^2 \), we can follow these steps: ### Step 1: Calculate the Initial Kinetic Energy (KE_initial) The formula for kinetic energy is given by: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is the mass of the body and \( v \) is the initial velocity. Substituting the values: \[ KE_{\text{initial}} = \frac{1}{2} m (60)^2 = \frac{1}{2} m (3600) = 1800m \, \text{Joules} \] ### Step 2: Calculate the Height (h) after 3 seconds We can use the second equation of motion to find the height: \[ s = ut + \frac{1}{2} a t^2 \] where: - \( u = 60 \, \text{m/s} \) (initial velocity) - \( a = -10 \, \text{m/s}^2 \) (acceleration due to gravity, negative because it acts downward) - \( t = 3 \, \text{s} \) Substituting the values: \[ s = (60)(3) + \frac{1}{2} (-10)(3^2) \] Calculating each term: \[ s = 180 - \frac{1}{2} \times 10 \times 9 = 180 - 45 = 135 \, \text{meters} \] ### Step 3: Calculate the Potential Energy (PE) at height h The formula for potential energy is: \[ PE = mgh \] Substituting the values: \[ PE = m \times 10 \times 135 = 1350m \, \text{Joules} \] ### Step 4: Calculate the Percentage of Kinetic Energy Converted to Potential Energy The percentage of kinetic energy converted to potential energy is given by: \[ \text{Percentage} = \left( \frac{PE}{KE_{\text{initial}}} \right) \times 100 \] Substituting the values: \[ \text{Percentage} = \left( \frac{1350m}{1800m} \right) \times 100 \] The mass \( m \) cancels out: \[ \text{Percentage} = \left( \frac{1350}{1800} \right) \times 100 = 0.75 \times 100 = 75\% \] ### Final Answer The percentage of the initial kinetic energy converted into potential energy after 3 seconds is **75%**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

A stone is projected vertically upward to reach maximum height h. The ratio of its kinetic energy to its potential energy at a height (4)/(5) h, will be

A particle of mass 2 kg is projected vertically upward with a velocity of 20 m/s. It attains maximum height of 17 m. The loss in mechanical energy due to air drag is ( g = 10 ms^-2)

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A body is projected with a velocity 60 ms ^(-1) at 30^(@) to horizontal . Its initial velocity vector is

A particle is projected vertically upwards with an initial velocity of 40 m//s. Find the displacement and distance covered by the particle in 6 s. Take g= 10 m//s^2.

A body is projected with velocity 60m/sec at 30 degree horizontal, its initial velocity vector is ? In the above problem velocity after 3 seconds is-

A body is projected horizontally with a velocity of u ms^(-1) at an angle theta with the horizontal. The kinetic energy at intial the highest point is (3)/(4)th of the kinetic energy. The value of theta is :

A body is projected horizontally from the top of a tower with a velocity of 30 m/s. The velocity of the body 4 seconds after projection is (g = 10ms^(-2) )

A car is travelling at a velocity of 10 m/s and has a mass of 850 kg. What is its kinetic energy?