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Two wires of equal length and cross-sect...

Two wires of equal length and cross-section area suspended as shown in figure. Their Young's modulus are `Y_(1)` and `Y_(2)` respectively. The equavalent Young's modulus will be

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`F = F_1+F_2 rArr (Y(2A)e)/(l) = (Y_1 Ae)/(l) + (Y_2 Ae)/(l)`
`2Y_(eq) = Y_1+Y_2 rArr Y_(eq) = (Y_1+Y_2)/(2)`
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