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A flask contains argon and chlorine in t...

A flask contains argon and chlorine in the ratio of 2:1 by mass. The temperature of the mixture is `27^(@) C`. Obtain the ratio of (i) average kinetic energy per molecule, and (ii) root mean square speed `V_(rms)` of the molecules of the two gases. Atomic mass of argon = 39.9 u, Molecular mass of chlorine = 70.9 u.

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The average kinetic energy of any gas(ideal) (i)The ration of average kinetic energy permolecule of the two gases =1:1(`because` oxygen and chlorine both have the same temperature in the flask)
(ii)We know that `(1)/(2)mV_(rms)^(2)=(3)/(2)K_(B)T` where m is the mass of the molcule
`therefore V_(rms )alpha (1)/(sqrt(M))`
(Or) `((V_(rms))Ar)/((V_(rms))Cl)=sqrt((m)_(Cl)/(m)_(Ar))=sqrt((M_(Cl))/(M_(Ar)))=sqrt((70.9)/(39.9))=1.33`
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