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An open pipe is in resonance in 2nd harm...

An open pipe is in resonance in 2nd harmonic with frequency `f_(1)`. Now one end of end of the tube is closed and frequency is increased to `f_(2)` such that the resonance again occurs in nth harmonic. Choose the correct option.

Text Solution

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In case `-lambda=l:.f_(1)=(v)/(lambda)=(v)/(l)`
In case `(2), lambda=(4l)/(n) :. f_(2)=(v)/(lambda)=(nv)/(4l)`
Here n is a odd number `f_(2)=(n)/(4)f_(1)`
for first resonance `n=5, f_(2)=(5)/(4) f_(1)` and since `f_(2) gt f_(1)`.
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