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Two identical sonometer wires have a fundamental frequency of `500 Hz` when kept under the same tension . The percentage change in tension of one of the wires that would cause an occurrence of `5 beats//s` , when both wires vibrate together is

Text Solution

Verified by Experts

Since `f prop sqrt(T)`
`:.(Deltaf)/(f)=(1)/(2)(DeltaT)/(T) So (DeltaT)/(T)=2xx(5)/(500)=0.02`
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