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(A): A person hears maximum sound at dis...

(A): A person hears maximum sound at displacement anti node (or) pressure node.
(B) : Two organ pipes of same length open at both ends produce sound of different pitch if their radii are different.
(C): If oil of density higher than water is filled in place of water in a resonance tube, its frequency remain unchanged.

A

All are true

B

A,B are only true

C

B are true

D

A,C are only true

Text Solution

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The correct Answer is:
A
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Two organ pipes of same length, open a bosh ends, produce sound of different frequencies if their radii are different. Why?

A pipe of length 1.5 m closed at one end is filled with a gas and it resonates at 30^(@)C in its fundamental with a tuning fork. Another pipe of the same length but open at both ends and filled with air and it resonates in its fundamental with the same tuning fork. Calculate the velocity of sound at 0^(@)C in the gas, given that the velocity of sound in air is 360 m s^(-1) at 30^(@) .

A glass capillary tube is of the shape of a truncated cone with an apex angle alpha so that its two ends have cross sections of different radii. When dipped in water vertically, water rises in it to a high h, where the radius of its cross section is b. If the surface tension of water is S, its density if rho , and its contact angle with glass is theta , the value of h will be (g is the acceleration due to gravity)

A glass capillary tube is of the shape of a truncated cone with an apex angle alpha so that its two ends have cross sections of different radii. When dipped in water vertically, water rises in it to a high h, where the radius of its cross section is b. If the surface tension of water is S, its density if rho , and its contact angle with glass is theta , the value of h will be (g is the acceleration due to gravity)

Find the greatest length of an organ pipe open at both ends that will have its fundamental frequency in the normal hearing range (20-20,000 Hz). Speed of sound in air = 340 ms^-1 .

A student performed the experiment to measure the speed of sound in air using resonance air-column method. Two resonances in the air-column were obtained by lowering the water level. The resonance with the shorter air-column is the first resonance and that with the longer air-column is the second resonance. Then, A. the intensity of the sound heard at the first resonance was more than at the second resonance B. the prongs of the tuning fork were kept in a horizontal plane above the resonance tube C. the ampitude of vibration of the end of the prongs is typically around 1 cm D. the length of the air-column at the first resonance was somewhat than 1//4 th of the wavelength of the sound in air.

A tube 1.0 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.3 m long and a mass of 0.01 kg . It is held fixed at both ends and vibrates in its fundamental mode. It sets the air column in the tube into vibration at its fundamental frequency by resonance. Find (a) the frequency of oscillation of the air column and (b) the tension in the wire. Speed of sound in air = 330 m//s .

Explain why (or how) : (a) In a sound wave, a displacement node is a pressure antinode and vice-versa, (b) Bats can ascertain distances, directions, nature and size of obstacles without any eyes, (c) a violin note and sitar note may have the same frequency, yet we can distinguish between the two notes, (d) Solids can support both longitudinal and transverse waves, but only longitudinal waves can propagate in gases, (e) The shape of pulse gets distorted during propagation in a dispersive medium.

Find the fundamental frequency and the first four overtones of a 15 cm pipe (a) if the pipe is closed at one end , and (b) if the pipe is open at both ends. ( c) How many overtones may be heard by a person of normal hearing in each of the above cases ? velocity of sound in air = 330 m//s .

A vertical pipe open at both ends is partially submerged in water . A tuning fork is unknown frequency is placed near the top of the pipe and made to vibrate . The pipe can be moved up and down and thus length of air column the pipe can be adjusted. For definite lengths of air column in the pipe, standing waves will be set up as a result of superposition of sound waves traveling in opposite directions. Smallest value of length of air column , for which sound intensity is maximum is 10 cm [ take speed of sound , v = 344 m//s ]. Answer the following questions. The air column here is closed at one end because the surface of water acts as a wall. Which of the following is correct ?

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