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(A): Wave velocity and particle velocity...

(A): Wave velocity and particle velocity for transverse wave are mutually perpendi cular to each other.
(R): The wave velocity and particle velocity have a constant ratio of their magnitudes

A

Both 'A' and 'R' are true and 'R' is the correct, explanation of 'A'.

B

Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A'

C

A' is true and 'R' is false

D

Both 'A' and 'R' are false

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the assertion and reason provided in the question, we will break down the concepts of wave velocity and particle velocity in transverse waves step by step. ### Step-by-Step Solution: 1. **Understanding Wave Velocity and Particle Velocity**: - In a transverse wave, the wave travels in a direction (let's say along the y-axis), while the particles of the medium oscillate perpendicular to this direction (along the x-axis). - Therefore, the wave velocity (v) is directed along the y-axis, and the particle velocity (u) is directed along the x-axis. 2. **Assertion Analysis**: - The assertion states that the wave velocity and particle velocity for transverse waves are mutually perpendicular to each other. - Since wave velocity is in the direction of wave propagation and particle velocity is in the direction of particle oscillation, they indeed are perpendicular. - **Conclusion**: The assertion (A) is true. 3. **Reason Analysis**: - The reason states that the wave velocity and particle velocity have a constant ratio of their magnitudes. - The wave velocity (v) can be expressed as \( v = \lambda f \), where \( \lambda \) is the wavelength and \( f \) is the frequency. - The particle velocity (u) can be derived from the wave equation. For a simple harmonic wave, it can be expressed as \( u = \frac{dy}{dt} = A \omega \cos(\omega t + \phi) \), where \( A \) is the amplitude, \( \omega \) is the angular frequency, and \( t \) is time. - The ratio of wave velocity to particle velocity is given by \( \frac{v}{u} = \frac{\lambda f}{A \omega \cos(\omega t + \phi)} \). - Since \( \lambda \), \( f \), and \( A \) are constants, but \( \cos(\omega t + \phi) \) varies with time, the ratio \( \frac{v}{u} \) is not constant. - **Conclusion**: The reason (R) is false. 4. **Final Conclusion**: - Since the assertion is true and the reason is false, the correct option is that A is true and R is false.
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