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(A): If two waves of same amplitude, pro...

(A): If two waves of same amplitude, produce a resultant wave of same amplitude, then the phase difference between them will be `120^(@)`
(R): The resultant amplitude of two waves is equal to sum of amplitude of two waves

A

Both 'A' and 'R' are true and 'R' is the correct, explanation of 'A'.

B

Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A'

C

A' is true and 'R' is false

D

Both 'A' and 'R' are false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided. **Assertion (A):** If two waves of the same amplitude produce a resultant wave of the same amplitude, then the phase difference between them will be \(120^\circ\). **Reason (R):** The resultant amplitude of two waves is equal to the sum of the amplitudes of the two waves. ### Step-by-Step Solution: 1. **Understanding the Waves:** - Let the two waves be represented as: - \( y_1 = a \sin(\omega t) \) - \( y_2 = a \sin(\omega t + \phi) \) - Here, \( a \) is the amplitude, \( \omega \) is the angular frequency, and \( \phi \) is the phase difference. 2. **Finding the Resultant Amplitude:** - The resultant wave \( y \) can be expressed as: \[ y = y_1 + y_2 = a \sin(\omega t) + a \sin(\omega t + \phi) \] - Using the sine addition formula, we can rewrite this as: \[ y = 2a \cos\left(\frac{\phi}{2}\right) \sin\left(\omega t + \frac{\phi}{2}\right) \] - The resultant amplitude \( A_r \) is given by: \[ A_r = 2a \cos\left(\frac{\phi}{2}\right) \] 3. **Setting Up the Condition:** - According to the assertion, the resultant amplitude is equal to the original amplitude \( a \): \[ A_r = a \] - Therefore, we have: \[ 2a \cos\left(\frac{\phi}{2}\right) = a \] - Dividing both sides by \( a \) (assuming \( a \neq 0 \)): \[ 2 \cos\left(\frac{\phi}{2}\right) = 1 \] 4. **Solving for Phase Difference:** - Rearranging gives: \[ \cos\left(\frac{\phi}{2}\right) = \frac{1}{2} \] - The angle whose cosine is \( \frac{1}{2} \) is \( 60^\circ \): \[ \frac{\phi}{2} = 60^\circ \implies \phi = 120^\circ \] - Thus, the assertion (A) is **true**. 5. **Evaluating the Reason (R):** - The reason states that the resultant amplitude of two waves is equal to the sum of the amplitudes of the two waves. - However, from our earlier analysis, we found that: \[ A_r = 2a \cos\left(\frac{\phi}{2}\right) \neq a + a \] - Therefore, the reason (R) is **false**. ### Conclusion: - The assertion (A) is true, while the reason (R) is false. Thus, the correct option is **3: A is true and R is false**.
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