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A source of sound is travelling towards ...

A source of sound is travelling towards a stationary observer. The frequency of sound heard by the observer is 25% more that the actual frequency. If the speed of sound is v, that of the source is

A

`(v)/(5)`

B

`(v)/(4)`

C

`(v)/(3)`

D

`(v)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the Given Information We know that: - The actual frequency of the sound emitted by the source is \( F_0 \). - The frequency heard by the observer is 25% more than the actual frequency, which can be expressed as: \[ F' = F_0 + 0.25F_0 = \frac{5}{4}F_0 \] - The speed of sound in the medium is \( v \). ### Step 2: Use the Doppler Effect Formula The formula for the frequency heard by a stationary observer when the source is moving towards the observer is given by: \[ F' = F_0 \frac{v}{v - v_s} \] where \( v_s \) is the speed of the source. ### Step 3: Substitute the Known Values Substituting \( F' \) with \( \frac{5}{4}F_0 \) in the Doppler effect formula, we have: \[ \frac{5}{4}F_0 = F_0 \frac{v}{v - v_s} \] ### Step 4: Cancel \( F_0 \) Since \( F_0 \) is common on both sides and is non-zero, we can cancel it out: \[ \frac{5}{4} = \frac{v}{v - v_s} \] ### Step 5: Cross Multiply to Solve for \( v_s \) Cross multiplying gives: \[ 5(v - v_s) = 4v \] Expanding this: \[ 5v - 5v_s = 4v \] ### Step 6: Rearrange the Equation Rearranging the equation to isolate \( v_s \): \[ 5v - 4v = 5v_s \] This simplifies to: \[ v = 5v_s \] ### Step 7: Solve for \( v_s \) Now, divide both sides by 5 to find \( v_s \): \[ v_s = \frac{v}{5} \] ### Conclusion The speed of the source \( v_s \) is: \[ \boxed{\frac{v}{5}} \]
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AAKASH SERIES-WAVES-EXERCISE-II (Doppler Effect : )
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