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A car travels at a speed of 'a' towards ...

A car travels at a speed of 'a' towards a high wall. The driver sounds a horn of frequency 'n'. If V is the velocity of sound in air, frequency of reflected sound heard by the driver is

A

`n(V+a)/(V-a)`

B

`n(V-a)/(V+a)`

C

`n(V+a)/(V)`

D

`n(V-a)/(V)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the frequency of the reflected sound heard by the driver in the car, we can break down the solution into clear steps. ### Step-by-Step Solution: 1. **Identify the Given Variables:** - Speed of the car (source) = \( a \) - Frequency of the horn (source frequency) = \( n \) - Velocity of sound in air = \( V \) 2. **Determine the Frequency Heard by the Wall (Observer):** - The car is moving towards a stationary wall. - The formula for the frequency heard by a stationary observer when the source is moving towards it is given by: \[ F_1 = F_0 \frac{V}{V - V_s} \] - Here, \( F_0 = n \) (the frequency of the horn), and \( V_s = a \) (the speed of the car). - Substituting these values into the formula: \[ F_1 = n \frac{V}{V - a} \] 3. **Determine the Frequency of the Reflected Sound Heard by the Driver:** - Now, the wall acts as a source of sound emitting frequency \( F_1 \), and the driver in the car is the observer moving towards this source. - The formula for the frequency heard by a moving observer when the source is stationary is: \[ F_2 = F_1 \frac{V + V_o}{V} \] - Here, \( V_o = a \) (the speed of the driver towards the wall). - Substituting for \( F_1 \): \[ F_2 = \left(n \frac{V}{V - a}\right) \frac{V + a}{V} \] 4. **Simplify the Expression:** - Simplifying \( F_2 \): \[ F_2 = n \frac{V (V + a)}{V(V - a)} = n \frac{V + a}{V - a} \] 5. **Final Result:** - The frequency of the reflected sound heard by the driver is: \[ F_2 = n \frac{V + a}{V - a} \]
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