From quantisation of angular momentum one gets for hydrogen atom, the radius of the `n^th` orbit as `r_n=((n^2)/(m_e))((h)/(2pi))^2((4piepsilon_0)/(e^2))`
For a hydrogen like atom of atomic number Z,

Options

A. the radius the first orbit will be the same
B. `r_(n)` will be greater for larger 'Z' values
C. `r_(n)`will be smaller for larger 'Z' values
D. None of these

Answer

C