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An alpha nucleus of energy (1)/(2)mv^(2)...

An alpha nucleus of energy `(1)/(2)mv^(2)` bomobards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

A

`(1)/(vartheta)`

B

`(1)/(Ze)`

C

`vartheta^(2)`

D

`(1)/(m)`

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The correct Answer is:
D
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AAKASH SERIES-ATOMS-EXERCISE -II
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  2. If an electron in hydrogen atom jumps from third orbit to second orbit...

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  3. An alpha nucleus of energy (1)/(2)mv^(2) bomobards a heavy nuclear tar...

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  4. In Rutherford's alpha particle cexperiment with thin gold faill, 8100 ...

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  5. An alpha particle of energy 5 MeV is scattered through 180^(@) by a fi...

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  7. The ratio of the largest to shortest wavelength in Balmer series of hy...

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  9. Light from balmer series of hydrogen is able to eject photoelectron fr...

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  10. A hydrogen atom emits a photon corresponding to an electron transition...

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  11. when an electron jumps from the fourth orbit to the second orbit, one ...

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  14. A hydrogen like atom (atomic number Z) is in a higher excited state o...

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  15. Electrons from n = 2 to n= 1 in hydrogen atom is made to fall on a met...

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  16. Let v(1) be the frequency of the series limit of the Lyman series, v(2...

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  17. The transition from the state n = 4 " to " n = 3 in a hydrogen like at...

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  19. What would be maximum wavelength for Brackett series of hydrogen-spect...

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  20. What would be the radius of second orbit of He^(+) ion?

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