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Condiser 3rd orbit of He^(+) (Helium),...

Condiser 3rd orbit of `He^(+)` (Helium), using non-relativistic approach, the speed of electron in this orbit will be (given `K=9xx10^(9)` constant, Z=2 and h (Planck's constant )=`6.6xx10^(-34)J-s)`

A

`0.73 xx 10^(6)` m/s

B

`3.0 xx 10^(8)` m/s

C

`2.92 xx 10^(6)` m/s

D

`1.46 xx 10^(6)` m/s

Text Solution

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The correct Answer is:
D
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Consider 3rd orbit of He^(+) (Helium) using nonrelativistic approach the speed of electron in this orbit will be (given K = 9 xx 10^(9) constant Z = 2 and h (Planck's constant) = 6.6 xx 10^(-34)Js .)

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