The frequency of amplitude modulated wave is equal to

Answer

Amplitude of both LSB and USB are equal and given by `=(mE_(c))/(2)=(0.5*80)/(2)=20"volts"`
Now frequency of LSB `=f_(c)-f_(s)=(1000-5)` kHz = 995 kHz
Frequency of USB `=f_(c)+f_(s)=(1000+5)` kHz = 1005 kHz

Explanation

Amplitude of both LSB and USB are equal and given by `=(mE_(c))/(2)=(0.5xx40)/(2)=20"volts"`
Now frequency of LSB `=f_(c)-f_(s)=(1000-5)` kHz = 995 kHz
Frequency of USB `=f_(c)+f_(s)=(1000+5)` kHz = 1005 kHz