A 400 W carner wave is modulated to a depth of 75%. Calculate the total power in the modulated wave.

Explanation

(i) Total power of modulated wave
`P_(tau)=P_(C)(1+(m^(2))/(2))=1000(1+(1^(2))/(2))=1500` watt
(ii) Power in USB `=1/2P_("SB")`
where power carried by side bands is given by Amplitude Modulation and Detection
`P_("SB")=P_(C)((m^(2))/(2))=1000((1^(2))/(2))=500` watt
`P_("USB")=1/2P_("SB")=1.2xx500=250` watt
(iii) Since power in LSB = Power in USB
`P_("LSB")=P_("USB")=250` watt