The maximum amplitude of the modulated wave is 16 v and minimum amplitude is 4 V. The percentage modulation is

Options

A. `25%`
B. `40%`
C. `60%`
D. `75%`

Answer

To find the percentage modulation given the maximum and minimum amplitudes of a modulated wave, we can follow these steps:

### Step 1: Identify the given values
- Maximum amplitude (E_max) = 16 V
- Minimum amplitude (E_min) = 4 V

### Step 2: Use the formula for percentage modulation
The formula for percentage modulation (m) is given by:

\[ m = \frac{E_{max} - E_{min}}{E_{max} + E_{min}} \times 100 \]

### Step 3: Substitute the values into the formula
Substituting the given values into the formula:

\[ m = \frac{16 V - 4 V}{16 V + 4 V} \times 100 \]

### Step 4: Calculate the numerator and denominator
- Numerator: \(16 V - 4 V = 12 V\)
- Denominator: \(16 V + 4 V = 20 V\)

### Step 5: Calculate the fraction
Now, we can calculate the fraction:

\[ m = \frac{12 V}{20 V} \times 100 \]

### Step 6: Simplify the fraction
Simplifying the fraction gives:

\[ m = 0.6 \times 100 \]

### Step 7: Calculate the percentage modulation
Finally, calculating the percentage gives:

\[ m = 60\% \]

### Final Answer
The percentage modulation is **60%**.

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