The phase and orientation of the electric field vector linked with electromagnetic wave differ from those of the corresponding magnetic field vector, respectively by:

Options

A. zero and zero
B. zero and `pi//2`
C. `pi//2` and zero
D. `pi//2` and `pi//2`

Answer

To solve the question about the phase and orientation differences between the electric field vector and the magnetic field vector in an electromagnetic wave, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Electromagnetic Waves**:
- Electromagnetic waves consist of oscillating electric (E) and magnetic (B) fields that are perpendicular to each other and to the direction of wave propagation.

2. **Phase Relationship**:
- In an electromagnetic wave, the electric field and magnetic field oscillate in phase. This means that when the electric field reaches its maximum value, the magnetic field also reaches its maximum value at the same time.

3. **Orientation Relationship**:
- The electric field vector and the magnetic field vector are oriented at right angles (90 degrees) to each other. This means that if the electric field is oscillating in one direction, the magnetic field will oscillate in a direction that is perpendicular to it.

4. **Quantifying the Differences**:
- The phase difference between the electric field and magnetic field is 0 radians (or 0 degrees) since they reach their peaks simultaneously.
- The orientation difference is 90 degrees (or π/2 radians) since the two vectors are perpendicular to each other.

5. **Conclusion**:
- Therefore, the phase difference is 0 and the orientation difference is π/2 (90 degrees).

### Final Answer:
- The phase and orientation of the electric field vector linked with electromagnetic waves differ from those of the corresponding magnetic field vector by: **Phase difference = 0, Orientation difference = π/2 (90 degrees)**.