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An electromagnetic wave going through va...

An electromagnetic wave going through vacuum is described by
` E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t)`.
Then

A

`E_(0)=B_(0)`

B

`E_(0)omega=B_(0)k`

C

`E_(0)B_(0)=omegak`

D

`E_(0)k=B_(0)omega`

Text Solution

Verified by Experts

The correct Answer is:
D
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