The maximum oxidaton state that fluorine exhibits is

Options

A. `-1`
B. zero
C. `+1`
D. `+2`

Explanation

To determine the maximum oxidation state that fluorine exhibits, we can follow these steps:

### Step 1: Understand the Concept of Oxidation States
Oxidation states (or oxidation numbers) indicate the degree of oxidation of an atom in a compound. The oxidation state can be positive, negative, or zero, depending on the element's electronegativity and the nature of its bonds.

**Hint:** Recall that electronegativity affects the oxidation state an element can exhibit.

### Step 2: Identify the Position of Fluorine in the Periodic Table
Fluorine (F) is located in Group 17 of the periodic table, which is known as the halogen group. It is the most electronegative element, meaning it has a strong tendency to attract electrons.

**Hint:** Consider how electronegativity influences the ability of an element to lose or gain electrons.

### Step 3: Determine Possible Oxidation States of Fluorine
Due to its high electronegativity, fluorine typically exhibits a negative oxidation state. The common oxidation states for fluorine are:
- **-1**: This occurs when fluorine gains an electron, as seen in compounds like HF (hydrogen fluoride).
- **0**: This occurs when fluorine is in its elemental form (F2).

**Hint:** Think about the compounds that fluorine forms and what oxidation states are present in those compounds.

### Step 4: Analyze the Given Options
The options provided are:
- -1
- 0
- +1
- +2

From our understanding:
- Fluorine can exhibit a -1 oxidation state (as in HF).
- It can exhibit a 0 oxidation state (as in F2).
- It does not exhibit positive oxidation states (+1 or +2) because it is highly electronegative and does not lose electrons.

**Hint:** Eliminate the options that do not fit with the known behavior of fluorine.

### Step 5: Conclusion
The maximum oxidation state that fluorine can exhibit is **0**, as it does not have positive oxidation states due to its electronegativity.

**Final Answer:** The maximum oxidation state that fluorine exhibits is **0**.