Oxidation number of Chlorine in chlorine heptaoxide is

Options

A. `+1`
B. `+4`
C. `+6`
D. `+7`

Explanation

To find the oxidation number of chlorine in chlorine heptaoxide (Cl2O7), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Formula**: The formula for chlorine heptaoxide is Cl2O7, which indicates that there are 2 chlorine atoms and 7 oxygen atoms in the compound.

2. **Assign Oxidation States**:
- Let the oxidation state of chlorine be \( x \).
- The oxidation state of oxygen is typically \(-2\).

3. **Set Up the Equation**:
- Since there are 7 oxygen atoms, the total contribution from oxygen to the oxidation state is \( 7 \times (-2) = -14 \).
- The total oxidation state of the compound must equal 0 because it is a neutral compound.
- Therefore, we can set up the equation:
\[ 2x + (-14) = 0 \]

4. **Solve for \( x \)**:
- Rearranging the equation gives:
\[ 2x - 14 = 0 \]
- Adding 14 to both sides:
\[ 2x = 14 \]
- Dividing both sides by 2:
\[ x = 7 \]

5. **Conclusion**: The oxidation number of chlorine in chlorine heptaoxide (Cl2O7) is \( +7 \).

### Final Answer:
The oxidation number of chlorine in chlorine heptaoxide is \( +7 \).