The speed of a train is reduced from 60 km/h, to 15 km/h, while it travels a distance of 450 m. If the retardation is uniform, find how much further it will travel before coming to rest ?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Convert Speeds from km/h to m/s
The initial speed \( u \) is given as 60 km/h. We convert it to meters per second using the conversion factor \( \frac{5}{18} \):
\[ u = 60 \times \frac{5}{18} = \frac{300}{18} = \frac{50}{3} \text{ m/s} \]

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