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In a car race, car A takes time t less t...

In a car race, car A takes time t less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point. Assuming that the cars start from rest and travel with constant accelerations `a_1` and `a_2` show that `v/t=sqrt(a_1a_2)` .

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To solve the problem step by step, we will use the equations of motion for uniformly accelerated motion. ### Given: - Car A takes time \( t \) less than car B. - Car A passes the finishing point with a velocity \( v \) more than car B. - Let the time taken by car A be \( T_1 \) and for car B be \( T_2 \). - Let the accelerations of car A and car B be \( a_1 \) and \( a_2 \) respectively. - From the problem, we have: ...
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