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If the velocity of a particle is v = At ...

If the velocity of a particle is `v = At + Bt^2`, where `A` and `B` are constant, then the distance travelled by it between `1 s` and `2 s` is :

A

`3/2 A+4B`

B

`3A+7B`

C

`3/2 A+7/3B`

D

`A/2+B/3`

Text Solution

Verified by Experts

The correct Answer is:
C
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