Home
Class 11
PHYSICS
Under the action of a force, a 2 kg body...

Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by `x=(t^(3))/(3)`, where x is in metre and t in second. The work done by the force in the first two seconds is

Text Solution

Verified by Experts

From work - energy theorem, `W = Delta KE`
`x=t^(3)//3 therefore` velocity `v=(dx)/(dt)=t^(2)`
At `t=0, v_(i)=0^(2)=0`, At `t=2, v_(f)=2^(2)=4 m//s`
work done `W=(1)/(2)m(v_(f)^(2)-v_(i)^(2))=(1)/(2)xx2(4^(2)-0)=16 J`
Promotional Banner

Similar Questions

Explore conceptually related problems

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .

Under the action of a force, a 1 kg body moves, such that its position x as function of time t is given by x=(t^(3))/(2). where x is in meter and t is in second. The work done by the force in fiest 3 second is

Under the action of foece, 1 kg body moves such that its position x as a function of time t is given by x=(t^(3))/(3), x is meter. Calculate the work done (in joules) by the force in first 2 seconds.

Under the action of a force a 2 kg body moves such that its position x in meters as a function of time t is given by x=(t^(4))/(4)+3. Then work done by the force in first two seconds is

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A foce acts on a 30g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

The position x of a particle moving along x - axis at time (t) is given by the equation t=sqrtx+2 , where x is in metres and t in seconds. Find the work done by the force in first four seconds

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.