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Calculate the power of an engine which c...

Calculate the power of an engine which can pull a mass of 500 metric ton up an incline rising I in 100 with a velocity of `10ms^(-1)`.

Text Solution

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`sin theta =(1)/(100). V=10 m//s, m=500xx10^(3)kg`
`F = mg sin theta = 500xx10^(3)xx9.8xx(1)/(100)=49xx10^(3)N`
Power `P = FV = 49xx10^(3)xx10=49xx10^(4)` watt = 490 KW.
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