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Two bodies of masses m(1) and m(2) are m...

Two bodies of masses `m_(1) and m_(2)` are moving with velocities `1ms^(-1) and 3ms^(-1)` respectively in opposite directions. If the bodies undergo one dimensional elastic collision, the body of mass `m_(1)` comes to rest. Final the ratio of `m_(1) and m_(2)`.

Text Solution

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`u_(1)=1 ms^(-1), u_(2)=-3 ms^(-1), v_(1)=0`
`v_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+((2m_(2))/(m_(1)+m_(2)))u_(2)`
`0 = ((m_(1)-m_(2))/(m_(1)+m_(2)))1+((2m_(2))/(m_(1)+m_(2)))(-3)`
`m_(1)-m_(2)=6m_(2), m_(1)=7 m_(2), (m_(1))/(m_(2))=(7)/(1)`
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