A sphere of mass `50 xx 10^(-3)` kg moving with a velocity of `2 ms^(-1)` hits another sphere which is at rest. Assuming the collision to be head - on collision and it they stick together after collision and move in the same direction with a velocity of `0.5 ms^(-1)`, find the moss of the second sphere

Explanation

`m_(1)=50xx10^(-3)kg, u_(1)=2 ms^(-1), u_(2)=0`,
`v=0.5 ms^(-1), v=v_(1)=v_(2)=0.5 ms^(-1)`.
`m_(1)u_(1)+m_(2)u_(2)=(m_(1)+m_(2))v`
`(50xx10^(-3))(2)+m_(2)(0)=[(50xx10^(-3))+m_(2)]0.5`
`m_(2)=(50xx10^(-3)xx2-50xx10^(-3)xx0.5)/(0.5)`
`= ((100-25))/(0.5)xx10^(-3)=150xx10^(-3)kg`