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A uniform ladder of mass 10 g leans agai...

A uniform ladder of mass 10 g leans agais ta smooth vertical wall making an angle of `53^0` with it. The other end rests on a rough horizontal floor. Find the normal force and the frictinal force that the floor exerts on the ladder

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The ladder is in equilibrium.
`therefore N_(1)=f` and `N_(2)=W`
Taking torque about .B.
`N_(1)(AO)=W(CB)`.
or `N_(1)(AB) cos 53 = W((AB)/(2))sin 53` or `N_(1)=(2)/(3)W`
and `N_(2)=W=10xx9.8=98 N`.
The frictional force is `f=N_(1)=(2)/(3)W=65 N`
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