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A circular beam of light of diameter (wi...

A circular beam of light of diameter (width) falls on a plane surface of glass. The angle of incidence is .I., angle of refraction is .r. and refractive index of glass is `mu`. Then the diameter of the refracted beam d. is…….

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Let d be the diameter of incident beam and d. be the diameter of refracted beam.
Then from figure `cos I = (d)/(PQ), d= PQ cos i`
From figure `cos r = (d.)/(PQ)" and "d.= PQ cos r`
i.e., `(d.)/(d)= (cos r)/(cos i) implies ("Diameter of refracted beam (d.)")/("Diameter of incident beam(d)")= (cos r)/(cos i)`.
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