In YDSE , the interfering waves have amplitude in the ratio 3 : 2. Find the ratio of maximum and minimum Amplitude of resultant wave.

Explanation

To solve the problem of finding the ratio of maximum and minimum amplitude of resultant waves in Young's Double Slit Experiment (YDSE) when the amplitudes of the interfering waves are in the ratio of 3:2, we can follow these steps:

### Step 1: Define the Amplitudes
Let the amplitudes of the two interfering waves be:
- \( A_1 = 3k \) (for the first wave)
- \( A_2 = 2k \) (for the second wave)

Here, \( k \) is a constant that can be any positive value.
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