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In the Young's double slit experiment ap...

In the Young's double slit experiment apparatus shown in figure, the ratio of maximum to minimum intensity on the screen is 9. The wavelength of light used is `lambda`, then the value of y is

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`(I"max")/(I"min")= ((sqrt(I_1)+sqrt(I_2))^2)/((sqrt(I_1)-sqrt(I_2))^2)=(9)/(1)`
or `(x+1)/(x-1)=3" where "x= sqrt((I_1)/(I_2))`
`therefore x=2 " "therefore (I_1)/(I_2)=4, " "I_(1)= 4I_(2)`
i.e., if `I_(2)= I_(0)" then "I_(1)= 4I_(0)`
`I_(0)= 4I_(0) cos^(2)""(phi)/(2)" " therefore phi= (2pi)/(3)`
`therefore ((2pi)/(lambda))((yd)/(D))= (2pi)/(3)" "therefore y= (lambda D)/(3d)`
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